Question

Una moto que marcha con una rapidez de 15 m/seg, aumenta su velocidad a razón de 1.5 m/seg². Calcular la distancia recorrida.​

Answer 1

Respuesta:

a = ( Vf - Vo )/t

t = ( Vf - Vo )/a

t = ?

a = 1.5m/s²

Vf = 15m/s

Vo = 0m/s

t = ( (15m/s-0m/s) )/1.5m/s²)

t = 15m/s/1.5m/s²

t = 15ms²/1.5ms

t = 15s²/1.5s

t = (15/1.5)s²/s ; 15/1.5 = 10

t = 10s

d = (at²)/2

d = ?

a = 1.5m/s²

t = 10s

d = ( (1.5m/s²)(10s)² )/2

d = ( 1.5m/s²(100s²))/2

d = ( 150ms²/s² )/2

d = ( 150m )/2

d = (150/2)m

d = 75m

R// La distancia recorrida es de 75m .