Question

una lata de aerosol de 325 ml de volumen contiene 3 g de propano como propelente.¿cual sera la presion en la lata a 28 ªc?

Answer 1

v = 325 mL /1000 = 0.325 L
T = 28 ºC + 273 = 301
m = 3 g C3H8 (PROPANO)
Mm propano = 44 g/mol

n(moles) = masa/ Mm

n = 3 g / 44  g/mol = 0.068 mol

R = 0.0821 (L x atm / mol x K)

p x v = n x R x T

P = n x R x T
       ````````````
           V
P = 0.068 mol x 0.0821 (L x atm / mol x K) x 301 K
       ``````````````````````````````````````````````````````````````
                           0.325 L

P = 5.17 Atm.