Question

una ayudita porfavor​

Answer 1

RESPUESTAS:

${1}^{ero} \frac{29}{60} \\ \\ {2}^{do} \frac{109}{120} \\ \\ {3}^{ero} \frac{20}{20} = 1$

RESOLUCIONES:

$\frac{3}{4} + \frac{5}{6} - \frac{1}{10} = \: ? \\ \\SOLUCIONES:\\ \\ 1) \: \: \frac{3}{4} + \frac{5}{6} = \frac{3 \times 3 + 2 \times 5}{12} = \frac{19}{12} = 1 \frac{7}{12} \\ \\ 2) \: \: 1 \frac{7}{12} - \frac{1}{10} = \frac{19}{12} - \frac{1}{10} = \frac{5 \times 19 - 6 \times 1}{60} = \frac{89}{60} = 1 \frac{29}{60}$

$\frac{7}{12} + \frac{3}{8} - \frac{1}{20} = \: ? \\ \\ SOLUCIONES: \\ \\ 1) \: \: \frac{7}{12} + \frac{3}{8} = \frac{2 \times 7 + 3 \times 3 }{24} = \frac{23}{24} \\ \\ 2) \: \: \frac{23}{24} - \frac{1}{20} = \frac{5 \times 23 - 6 \times 1}{120} = \frac{109}{120}$

$\frac{3}{4} + \frac{2}{5} - \frac{3}{20} = \: ? \\ \\ SOLUCIONES: \\ \\ 1) \: \: \frac{3}{4} + \frac{2}{5} = \frac{5 \times 3 + 4 \times 2}{20} = \frac{23}{20} = 1\frac{3}{20} \\ \\ 2) \: \: 1\frac{3}{20} - \frac{3}{20} = \frac{23}{20} - \frac{3}{20} = \frac{23 - 3}{20} = \frac{20}{20} = 1$