Un volumen de 1.34 lit de un gas, medido 19°c y 0.97 atm tiene una masa de 2.55 g. Calcula la masa molecular del gas
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Ley de los gases ideales
V · P = n · R · T sustituir n
n = masa/Mm
V · P = masa · R · T despejar Mm
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Mm
Mm = m · R · T
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V · P
R = 0.0821 (L atm/mol K)
T = 19 ºC + 273 = 292 K
P = 0.97 atm
V = 1.34 L
m = 2.55 g
Mm = 2.55 g · 0.0821 (L atm / mol K) · 292 K
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0.97 atm · 1.34 L
Mm = 47.03 g/mol
V · P = n · R · T sustituir n
n = masa/Mm
V · P = masa · R · T despejar Mm
``````````
Mm
Mm = m · R · T
``````````````
V · P
R = 0.0821 (L atm/mol K)
T = 19 ºC + 273 = 292 K
P = 0.97 atm
V = 1.34 L
m = 2.55 g
Mm = 2.55 g · 0.0821 (L atm / mol K) · 292 K
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0.97 atm · 1.34 L
Mm = 47.03 g/mol
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