Question

un movil parte del reposo y en 4s recorre 50m con aceleracion constante ¿ en que tiempo recorrera 112,5m?

Answer 1

Los datos son:

Vo = 0
t =4s
d = 50m
a = ?
                           De la Cinemática del MRUA conocemos
                                       d = Vot + 1/2 at²
                                       50 = 0  + 1/2 a(4)²
                                       50 = 8a
                                         a = 6,25 m/s²
t = ?     d = 112,5m
                                     d = Vot + 1/2 at²
                              112,5 = 0 + 1/2 (6,25)t²
                              112,5 = 3,13t²
                                     t² = 36
                                     t  = 6s