Un gas ocupa un volumen de 520 ml a 25°C y 650 mmHg de presion. Calcula el volumen que ocuparia el gas a 700 mmHg y 32°C
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Ley general de los gases
V1 · P1 = V2 · P2
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T1 T2
T1 = 25 ºC + 273 = 298 K
V1 = 520 mL / 1000 = 0.520 L
P1 = 650 mmHg / 760 = 0.86 atm
T2 = 32 ºC + 273 = 305 K
V2 = ?
P2 = 700 mmHg/ 760 = 0.92 atm
calcular V2
V2 = 0.520 L · 0.86 atm · 305 K
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0.92 atm · 298 K
V2 = 0.498 L
V2 = 0.498 x 1000 = 498 mL
V1 · P1 = V2 · P2
`````````` ``````````
T1 T2
T1 = 25 ºC + 273 = 298 K
V1 = 520 mL / 1000 = 0.520 L
P1 = 650 mmHg / 760 = 0.86 atm
T2 = 32 ºC + 273 = 305 K
V2 = ?
P2 = 700 mmHg/ 760 = 0.92 atm
calcular V2
V2 = 0.520 L · 0.86 atm · 305 K
``````````````````````````````````````
0.92 atm · 298 K
V2 = 0.498 L
V2 = 0.498 x 1000 = 498 mL
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