Question

Un gas ocupa un volumen de 200 litros a 95 ºC y 782 mmHg ¿Cuál será el volumen ocupado por dicho gas a 65 ºC y 815 mmHg?

Answer 1

Respuesta:

V1 P1 T2 = V2 P2 T1

K = ºC  + 273

V1 = 200 L

T1 = 95 + 273 = 368 K

P1 = 782 mmHg

V2 = ?

T2 = 65 + 273 = 338 K

P2 = 800 mmHg

V2 = 200 L x 782 x 338 K

      ````````````````````````````

        800 mmHg x 368 K

V2 = 179,56 L

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SI SE TRANSFORMA LA PRESION DE mmHg a atm

V1 = 200 L

T1 = 95 + 273 = 368 K

P1 = 782 mmHg / 760 = 1.028 atm

V2 = ?

T2 = 65 + 273 = 338 K

P2 = 800 mmHg / 760 = 1.052 atm

V2 = 200 L x 1.028 atm x 338 K

      ````````````````````````````````````

        1.052 atm x 368 K

V2 = 179.50 L

Explicación:

Answer 2

Respuesta:

v2 es igual a 176.25 litros

Explicación:

Espero haberte ayudado.