Un gas ocupa 0,8m³ a 305 K y 1,82x10⁶ Pa. -Calcula a que presión estarà sometido si doblamos el volumen y mantenemos la temperatura constante.
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Ley de los gases ideales
P x V = n x R x T
R = 8.3144 (Pa x m³ / K mol)
v = 0.8 m³
T = 305 K (constante)
Pa = 1.82 x 10⁶
1. calcular moles
n = 1.82 x 10⁶ Pa x 0.8 m³
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8.3144 (Pa x m³/mol K) x 305 K
n = 574.15 mol
2. calcular el volumen y como se duplica el volumen = 2 (0.8 m³) = 1.6 m³
P = 574.15 moles x 8.3144 Pa x 305 K
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1.6 m³
P = 909988.99 Pa
P x V = n x R x T
R = 8.3144 (Pa x m³ / K mol)
v = 0.8 m³
T = 305 K (constante)
Pa = 1.82 x 10⁶
1. calcular moles
n = 1.82 x 10⁶ Pa x 0.8 m³
`````````````````````````````````````````````
8.3144 (Pa x m³/mol K) x 305 K
n = 574.15 mol
2. calcular el volumen y como se duplica el volumen = 2 (0.8 m³) = 1.6 m³
P = 574.15 moles x 8.3144 Pa x 305 K
````````````````````````````````````````````````
1.6 m³
P = 909988.99 Pa
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