Un gas desconocido ocupa un volumen de 20 L a 40°C y a 770 torr. ¿Cuál será la presión en torr de este gas si el nuevo volumen es de 75,0 L a 0°C?
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v1 = 20 L
P1 = 770 Torr
T = 40 + 273 = 313 K
V2 = 75,0 L
P2 = ?
T2 = 0 + 273 = 273 K
V1 x P1 = V2 x P2
```````````` ``````````````
T1 T2
P2 = V1 x P1 x T2
``````````````````````
V2 x T1
P2 = 20 L x 770 torr x 273 K
````````````````````````````````
75,0 L x 313 K
P2 = 179,09 Torr
P1 = 770 Torr
T = 40 + 273 = 313 K
V2 = 75,0 L
P2 = ?
T2 = 0 + 273 = 273 K
V1 x P1 = V2 x P2
```````````` ``````````````
T1 T2
P2 = V1 x P1 x T2
``````````````````````
V2 x T1
P2 = 20 L x 770 torr x 273 K
````````````````````````````````
75,0 L x 313 K
P2 = 179,09 Torr
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