Química, pregunta formulada por vanesamoran1, hace 1 año

Trióxido de di hierro. (Sol. 159,6 u)
C3H6 (Sol. 42 u)
Nitrato de potasio. (Sol. 101,1 u)
C2H6O (Sol. 46 u) Nesesito Esto Urgente Para Mañana Muchas Gracias

Respuestas a la pregunta

Contestado por snorye
1
Fe2O3

Fe = 2 X 55.84 = 111.68 g/mol
 O =  3 x 15.99 = 47.97 g/mol
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               Mm = 159.65 g/mol

C3H6
C =  3 x 12 = 36 g/mol
H = 6 x 1 = 6 g/mol
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              Mm = 42 g/mol

KNO3
K = 1 x 39.09 g/mol
N = 1 x 14 = 14 g/mol
O = 3 x 15.99 = 47.97 g/mo`l
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               Mm = 101.06 g/mol

C2H6O
C: 2 x 12 = 24 g/mol
H: 6 x 1 = 6 g/mol
O: 1 x 16 = 16 g/mol
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         Mm = 46 g/mol
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