Question

TRANSFORMA

490 mmHg →? atm
303 K →? °C
-17°C →? K
548 mL →?L
2,5 atm → ? mm Hg ​

Answer 1

Respuesta:

a. 490 mmHg → atm =  0.644 atm

b. 303 K → ºC = 29.85 ºC

c. -17°C →  K = 256.15 K

d. 548 mL → L = 0.548 L

e.  2,5 atm → mm Hg ​= 1900 mmHg

Explicación:

TRANSFORMA

a. 490 mmHg →? atm

1 atm --- 760 mmHg

    x   ---  490 mmHg

     x = 0.644 atm

b. 303 K → °C

    ºC = K - 273.15

     ºC = 303 - 273.15

      ºC = 29.85

c. -17°C → K

    K = ºC + 273.15

    K = -17 + 273.15

    K = 256.15

d. 548 mL → L

    V = 548  / 1000

    V = 0.548 L

e.  2,5 atm → mm Hg ​

          760 mmHg --- 1 atm

                    x        ---- 2.5 atm

                   x = 1900 mmHg