Question

The sum of three ages is 88. The first is 20 years more than the second and the third is 18 years less than the first. Find the ages

Answer 1

Explicación paso a paso:

Let x be first age, y second and z third

x+y+z=88

x+20 = y

x-18= z

Now we change the equation

x+x+20+x-18=88

3x+2=88

3x=86

x= 86/3

x= 86/3

y= 86/3+20 = 146/3

z= 86/3-18 = 32/3