Question

$(x + 6) {}^{2}$
$(4x + 7) { }^{2}$
$(4a + 6) {}^{2}$
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Answer 1

Respuesta:

Explicación paso a paso:

Resolvemos aplicando la fórmula de producto notable

                                $(a+b)^{2} =a^{2} +2a.b+b^{2}$

$(x+6)^{2} = x^{2} +2.x.6+6^{2} = x^{2} +12x+36\\\\\\(4x+7)^{2} = (4x)^{2} +2.(4x).7+7^{2} = 16x^{2} +56x+49\\\\\\\\(4a+6)^{2} = (4a)^{2} +2.(4a).6+6^{2} = 16a^{2} +48a+36$