Question

$\\ x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} \pi x_{123} x_{123} \alpha \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \beta \\ x^{2} x^{2} \leq \geq x^{2} x^{2}$

Answer 1

Respuesta:

no le entiendo amigo