Question

$\sqrt{(X+1)^{2}-(X+2)^{2}-(X+3)^{2}+(X+4)^{2}$

Answer 1

Respuesta:

$=\sqrt{-x^2-7x-8}$

Explicación paso a paso:

$\sqrt{\left(x+1\right)^2-\left(x+2\right)^2-\left(x+3\right)^2+\left(x+4\right)}\\\\\\=\sqrt{\left(x+1\right)^2-\left(x+2\right)^2-\left(x+3\right)^2+x+4}\\\\\\=\sqrt{-x^2-7x-8}$