Question

$\sqrt{96}$
$\sqrt{766 {}^{4} }$
$\sqrt{36c}$
$\sqrt{819}$
$\sqrt{129a} {}^{2}$
$\sqrt{27ab {}^{2} }$
$\sqrt{32a {}^{13} } 2 {}^{5}$

ayuda porfa

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Answer 1

NUMBER 1

$\sqrt{96} =$

$= \sqrt{16 \times 6}$

$= \sqrt{ {4}^{2} \times 6}$

$= \sqrt{ {4}^{2} } \sqrt{6}$

$= 4 \sqrt{6}$

NUMBER 2

$\sqrt{ {766}^{4} } =$

$= \sqrt[2]{766} {}^{4}$

$= {766}^{2}$

NUMBER 3

$\sqrt{36c} =$

$= \sqrt{ {6}^{2}c }$

$= \sqrt{ {6}^{2} } \sqrt{c}$

$= 6 \sqrt{c}$

NUMBER 4

$\sqrt{819} =$

$= \sqrt{9 \times 91}$

$= \sqrt{ {3}^{2} \times 91 }$

$= \sqrt{ {3}^{2} } \sqrt{91}$

$= 3 \sqrt{91}$

NUMBER 5

$\sqrt{129 {a}^{2} } =$

$= \sqrt{ {a}^{2} } \sqrt{129}$

$= a \sqrt{129}$

$= \sqrt{129} a$

NUMBER 6

$\sqrt{27a {b}^{2} } =$

$= \sqrt{ {3}^{3} {ab}^{2} }$

$= \sqrt{ {3}^{2 + 1} \times {ab}^{2} }$

$= \sqrt{ {3}^{2} \times {3}^{1} {ab}^{2} }$

$= \sqrt{ {3}^{2} \times {3ab}^{2} }$

$= \sqrt{ {3}^{2} } \sqrt{ {b}^{2} } \sqrt{3a}$

$= 3b \sqrt{3a}$

NUMBER 7

$\sqrt{ {3a}^{13} {2}^{5} } =$

$= {2}^{2} {a}^{6} \sqrt{6a}$

$= {4a}^{6} \sqrt{6a}$

$\sf\red{✧ Correct \: Me \: If \: I'm \: Wrong ✧}$

$\fcolorbox{red}{pink}{ -- Answer By @balQis01 || Brainly -- }$