Question

$si: (x+n )^2= x^2 + 16 x +64calcular[tex]si (x+n)^{2} =x^{2} + 16x + 64\\calcular \sqrt[3]{n}$

Answer 1

Respuesta:

2

Explicación paso a paso:

$\left(x+n\right)^2=x^2+16x+64$

---------------------------------------------

$x+n=\sqrt{x^2+16x+64}\\x+n-x=\sqrt{x^2+16x+64}-x$

---------------------------------------------

$x+n-x\\x-x=0\\=0$

----------------------------------------------

$\sqrt{x^2+16x+64}-x\\=x+8-x\\=x-x+8\\x-x=0\\=8$

Hallar $\sqrt[3]{n}$:

$\sqrt[3]{8}\\8=2^3\\=2$