Question

$Si P(x)= (3x^{3} - 8) + (x-2) (x^{2} + 2x + 4) \\Hallar, P(5)$

Answer 1

Respuesta:

listo

Explicación paso a paso:

$\left(3x^3-8\right)+\left(x-2\right)\left(x^2+2x+4\right)\\\\\\x=3x^3-8+\left(x-2\right)\left(x^2+2x+4\right)\\\\\\x=3x^3-8+x^3-8\\\\\\=4x^3-16$

ahora hallar P(5)

$\left(3\left(5\right)^3-8\right)+\left(\left(5\right)-2\right)\left(\left(5\right)^2+2\left(5\right)+4\right)\\\\\\=367+\left(\left(5\right)-2\right)\left(\left(5\right)^2+2\left(5\right)+4\right)\\\\\\=367+3\left(\left(5\right)^2+2\left(5\right)+4\right)\\\\\\=367+3\cdot \:39\\\\\\=367+117\\\\\\=484$