Question

$\sec0 \times \csc(0)$
A) 15/4
B)10/3
C)7/5
D)13/10
E)15/11​

Answer 1

Respuesta:

b ) P = 10/3

Explicación paso a paso:

Hallamos la hipotenusa:

h^2 = 1^2 + 3^2

h^2 = 1 + 9

h^2 = 10

h = √10

P = secθ*cscθ

P = (1/cosθ)*(1/senθ)

P = [1/(3/√10)]*[(1/(1/√10)]

P = (√10/3)*((√10/1)

P = 10/3