Question

$Log_{2} (2x^{2})- Log_{2}(6x) = 10$
PORFA....

Answer 1

Respuesta:

La solución es 3072

Explicación:

•

$Log_{2} (2x^{2})- Log_{2}(6x) = 10 \\ \\ log_{2 }( \frac{2 {x}^{2} }{6x} ) = 10 \\ \\ \frac{ {2x}^{2} }{6x } = {2}^{10} \\ \\ \frac{ {2x}^{2} }{6x} = 1024 \\ \\ 2 {x}^{2} = 6x.(1024) \\ \\ 2 {x}^{2} = 6144x \\ \\ {2x}^{2} - 6144x = 0 \\ \\ x.(2x - 6144) = 0 \\ \\ x = 0 \\ \\ \\ 2x - 6144 = 0 \\ \\ 2x = 6144 \\ \\ x = \frac{6144}{2} \\ \\ x = 3072$