Question

$( \frac{5}{7} {a}^{2} + \frac{1}{8} n {)}^{2}$
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Answer 1

Respuesta:

$\left(\frac{5}{7}a^2+\frac{1}{8}n\right)^2$

$a^{2} =a^{2}$

$\frac{5}{7}a^2=\frac{5a^2}{7}$

$\frac{1}{8}n=\frac{n}{8}$

$\boxed{\left(\frac{5a^2}{7}+\frac{n}{8}\right)^2}$