Question

$\frac{4}{2^{4} } - \frac{1}{3^{ - 1} } + \frac{2 ^{2} \times 4 }{32} \times \sqrt{ \frac{3 ^{7} }{3^{3} } }$
$3^{ - 2} \times \frac{1}{3} \times {3}^{6} + \sqrt[]{ \sqrt[]{ \frac{625}{81} } } + (\frac{2}{3 } ) ^{ - 1}$
$\frac{ \sqrt{10} \times \sqrt{6} }{ \sqrt{15} } - ( \frac{1}{2} ) ^{4} \div {2}^{ - 2} + \sqrt{ \frac{ \sqrt{8} \times \sqrt{8} }{27} }$
ayuda porfavor​

Answer 1

Respuesta:

⇒$\frac{13}{8}$

⇒$\frac{181}{6}$

⇒$\frac{63-8\sqrt{6} }{36}$

Explicación paso a paso:

$\frac{4}{2^4} -\frac{1}{3^-1} + \frac{2^2*+4}{32} *\sqrt{\frac{3^7}{3^3} }$

$\frac{2}{16} -\frac{1}{\frac{1}{3} } +\frac{16}{32} *\sqrt{3^4}$

$\frac{1}{8} -3+\frac{1}{2} *9$

$\frac{1}{8} -3+\frac{9}{2}$

$\frac{1-24+36}{8}$

⇒$\frac{13}{8}$

$3^{-2} *\frac{1}{3} *3^6+\sqrt{\sqrt{\frac{645}{81} } } +(\frac{2}{3} )^-1$

$\frac{1}{9} *\frac{729}{3} +\sqrt{\sqrt{\frac{5^4}{3^4} } } +\frac{3}{2}$

$27+\frac{5}{3} +\frac{3}{2}$

$\frac{162+10+9}{6}$

⇒$\frac{181}{6}$

$\frac{\sqrt{10}*\sqrt{6} }{\sqrt{15} } -(\frac{1}{2} )^4 /2^-2+\sqrt{\frac{\sqrt{8} *\sqrt{8} }{27} }$

$\frac{2\sqrt{15} }{\sqrt{15} } -\frac{1}{16} / \frac{1}{4} +\sqrt{\frac{8}{27} }$

$2-\frac{1}{4} +\frac{2\sqrt{6} }{9}$

$\frac{72-9+8\sqrt{6} }{36}$

⇒$\frac{63-8\sqrt{6} }{36}$