Question

$9x - 11y + 8x - 6x$
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Answer 1

Respuesta:

$x^2-x-6=0$  

$-x+3>2x+1$  

$recta\:\left(1,\:2\right),\:\left(3,\:1\right)$  

$f\left(x\right)=x^3$  

$verificar\:\tan^2\left(x\right)-\sin^2\left(x\right)=\tan^2\left(x\right)\sin^2\left(x\right)$  

$\frac{d}{dx}\left(\frac{3x+9}{2-x}\right)$

 

$\left(\sin^2\left(\theta\right)\right)'$  

$\sin\left(120\right)$  

$\lim_{x\to0}\left(x\ln\left(x\right)\right)$  

$\int e^x\cos\left(x\right)dx$  

$\int_0^{\pi}\sin\left(x\right)dx$  

$\sum_{n=0}^{\infty}\frac{3}{2^n}$

 

Explicación paso a paso: