Question

$8x { }^{2} - 12x = 0$
$x {}^{2} - 24x + 128 = 0$
$4x { }^{2} - 625 = 0$
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Answer 1

Respuesta:

$1)4x(2x - 3) = 0 \\ x = 0 \\ 2x - 3 = 0\to \: x = \frac{ - 3}{2}$

$2). \: x {}^{2} - 24x + 128 = 0 \\ (x - 16)(x - 8) = 0 \\ x - 16 = 0\to \: x = 16 \\ x - 8 = 0\to \: x = 8$

$3).4x { }^{2} - 625 =0 \\ {(2x)}^{2} - 25 {}^{2} = 0 \\ (2x + 25)(2x - 25) = 0 \\ 2x + 25= 0\to \: x = - 12.5 \\ 2x - 25= 0\to \: x = 12.5$