Question

$(3y {}^{3}) {}^{4} (4y {}^{2} ) {}^{ - 3}$
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Answer 1

Respuesta:

$\boxed{\dfrac{81}{64}y^{6}}$

 

Explicación paso a paso:

Se simplifica de acuerdo a la ley de exponentes:

$(3y^3)^4(4y^2)^{-3}\\\\(3)^4(y^3)^4(4)^{-3}(y^2)^{-3}\\\\(3\times3\times3\times3)(y^{3\times4})(4^{-3})(y^{2\times-3})\\\\81 y^{12}\left( \dfrac{1}{4^{3}} \right)(y^{-6})\\\\\\81 y^{12}\left( \dfrac{1}{4\times4\times4} \right)\left(\dfrac{1}{y^6} \right)\\\\\\81 y^{12}\left( \dfrac{1}{64} \right)\left(\dfrac{1}{y^6} \right)\\\\\\\left(\dfrac{81}{64} \right) \left(\dfrac{y^{12} }{y^6} \right)\\\\\\\left(\dfrac{81}{64} \right)(y^{12-6})\\\\\\\boxed{\dfrac{81}{64}y^{6}}$