Question

$2(x + 3) + 3.(x - 1) < 4(x +)$
$x - 3 + 2(x + 1) \leqslant x - 2$
$3(x + 2) - 4.(x - 3) \geqslant 10$

Answer 1

x-3+2(x+1 ) ≤ x-2

x-3+2x+2 ≤ x-2

x+2x-x ≤ -2+3-2

2x ≤ -1

x ≤-1/2

3(x+2)-4(x-3) ≥ 10

3x+6-4x+12 ≥ 10

3x-4x ≥ 10-6-12

-x ≥ -8

x ≤ 8