Question

$(2 \times - 3y - 7) { }^{2} =$
Matemáticas ayuda​

Answer 1

Respuesta:

$\left(2x-3y-7\right)^2=\\\\\\\left(2x-3y-7\right)^2=\left(2x-3y-7\right)\left(2x-3y-7\right)\\=\left(2x-3y-7\right)\left(2x-3y-7\right)\\=4x^2-12xy-28x+9y^2+42y+49\\\\Resultado=4x^2-12xy-28x+9y^2+42y+49$