Question

$(16b²+72b-32)÷8$

Answer 1

Explicación paso a paso:

$\frac{16 {b}^{2} + 72b - 32}{8} = \\ \\ \frac{16 {b}^{2} }{8} + \frac{72b}{8} - \frac{32}{8} \\ \\ \frac{(2)(8) {b}^{2} }{8} + \frac{(9)(8)b}{8} - \frac{(4)(8)}{8} = \\ \\ 2 {b}^{2} + 9b - 4$