Question

Teoria de exponentes

P = [4 ^ - 1 + 5 + 7/4 - 2(- 6 ^ 0)] ^ (2 ^ - 1)​

Answer 1

Respuesta:

Explicación:

P = [ $4^{-1}$ + 5 + $\frac{7}{4}$ - 2($6^{0}$) $]^{2^{-1} }$

P = [ $\frac{1}{4^{1} }$ + 5 + $\frac{7}{4}$ - 2(1) $]^{2^{-1} }$

P = [ $\frac{1}{4 }+\frac{7}{4}$ + 5 - 2 $]^{2^{-1} }$

P = [ $\frac{1+7}{4 }$ + 3 $]^{2^{-1} }$

P = [ 2 + 3 $]^{\frac{1}{2} }$

P = $5^{\frac{1}{2} } = \sqrt{5}$