tengo un recipiente de 200cm3 a 20°C el gas del recipiente ejerce una presion de 900mmHg. lo paso a un reciepiente de 0.5l. A cuanto °C lo debo poner para que ejrerce una presion de 1.5 atm
Respuestas a la pregunta
Contestado por
2
Resipiente 1 Resipiente 2
V1= 200cm^2 --->0.2 L V2=0.5 L
T1=20ºC T2= ??
P1=900/760 atm P2=1.5 atm
P1V1T2=P2V2T1
T2=P2V2T1/P1V1
T2=1.5 atm x 0.5 L x 20ºC/1.18 atm x 0.2 L
T2=63.33 ºC
V1= 200cm^2 --->0.2 L V2=0.5 L
T1=20ºC T2= ??
P1=900/760 atm P2=1.5 atm
P1V1T2=P2V2T1
T2=P2V2T1/P1V1
T2=1.5 atm x 0.5 L x 20ºC/1.18 atm x 0.2 L
T2=63.33 ºC
Contestado por
1
Ley general de los gases
V1 P1 = V2 P2
`````````` ``````````
T1 T2
V1 = 200 / 1000 = 0.20 L
P1 = 900 mmHg
T1 = 20 + 273 = 293 K
V2 = 0.5 L
P2 = 1.5 atm
T2 = ?
1.18 atm x 0.200 L = 1.5 atm x 0.5 L
``````````````````````````` ``````````````````````
293 K T2
0.236 atm L = 0.75 atm L
```````````````` ````````````````
293 T2
0.000805 T2 = 0.75 atm L
T2 = 0.75 / 0.000805
T2 = 931 K
ºC = K - 273
ºC = 931 - 273 = 658 ºC
V1 P1 = V2 P2
`````````` ``````````
T1 T2
V1 = 200 / 1000 = 0.20 L
P1 = 900 mmHg
T1 = 20 + 273 = 293 K
V2 = 0.5 L
P2 = 1.5 atm
T2 = ?
1.18 atm x 0.200 L = 1.5 atm x 0.5 L
``````````````````````````` ``````````````````````
293 K T2
0.236 atm L = 0.75 atm L
```````````````` ````````````````
293 T2
0.000805 T2 = 0.75 atm L
T2 = 0.75 / 0.000805
T2 = 931 K
ºC = K - 273
ºC = 931 - 273 = 658 ºC
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