Question

Tema: Ángulo Doble

Hallar el valor de : tg106°

Answer 1

${tan(2x)=\frac{2tanx}{1-tan^2x}}\\\\{tan(106)=tan(2(53))}\\\\{tan106= \frac{2tan(53)}{1-tan^2(53)}}\\\\{tan(106)= \frac{2(\frac{4}{3})}{1-(\frac{4}{3})^2} }\\\\{tan(106)= \frac{\frac{8}{3}}{1-\frac{16}{9}} }\\\\{tan(106)=\frac{\frac{8}{3}}{-\frac{7}{9}}}\\\\{tan(106)=\frac{8}{3} \times -\frac{9}{7}}}\\\\{tan(106)= -\frac{24}{7} }$