Question

(tana+cota)=seca+csca

Answer 1

Respuesta:

1=sen(a)+cos(a)

Explicación paso a paso:

tan(a)+cotg(a)=sec(a)+csc(a)

(sen(a)/cos(a))+(cos(a)/sen(a))=1/cos(a)+1/sen(a)

$(sen^2(a)+cos^2(a))/sen(a)cos(a) =(cos(a)+sen(a))/cos(a)sen(a)\\1/(cos(a)sen(a))=(cos(a)+sen(a))/cos(a)sen(a)\\1=sen(a)+cos(a)$

Espero te sirva :)