Question

(t - 3)²-(t - 2)²= 5
Por favor!

Answer 1

Solucion:
$t^{2}-6t+9-(t^{2}-4t+4)=5$
$t^{2}-6t+9-t^{2}+4t-4= 5$
-2t+5= 5
-2t= 0
t= 0

Answer 2

Desarrollamos los productos notables:

(t-3)² - (t-2)² = 5
t²-6t+9-(t²-4t+4)= 5
t²-6t+9-t²+4t-4= 5

Se va t²:
-6t+9+4t-4= 5
-2t+5=5
-2t=0
t= 0/-2
∴ t=0