Question

Suma o diferencia de binomios al cuadrado
(x+7)²=
(3a-4b)²=
(5p³+2q⁶)²=
(c-9)²=

Answer 1

Respuesta:

Explicación paso a paso:

$(x+7)^{2=x^{2}+2.x.7+7^{2} = x^{2}+14x+49$

$(3a-4b)^{2} =(3a)^{2}-2.(3a).(4b)+(4b)^{2} = 9a^{2}-24ab+16b^{2}$

$(5p^{3}+2q^{6})^{2} =(5p^{3})^{2}+2.(5p^{3}).(2q^{6})+(q^{6})^{2} = 25p^{6}+20p^{3}q^{6}+4q^{12}$

$(c-9)^{2}=c^{2}-2.c.9+9^{2} = c^{2}-18x+81$