Question

suma de polimonio(4x²-8x-1)+(5x²+6x+5)
(11x⁴+9x³-x²-18)+(9x⁴-5x³-8x²-1)
resta de polinomio
(6x²-15x-1)-(4x²+7x+3)
(10u²-3u-15)-(15u²+5u-15)
multiplicación de monomio
(x³) (21xy)
(xy) (-5x⁴y)
(4x2) (5x²+6x-7)
​

Answer 1

Respuesta:

Fácil

suma de polinomio

(4x²-8x-1)+(5x²+6x+5)  (11x⁴+9x³-x²-18)+(9x⁴-5x³-8x²-1)

$\left(4x^2-8x-1\right)+\left(5x^2+6x+5\right)\left(11x^4+9x^3-x^2-18\right)+\left(9x^4-5x^3-8x^2-1\right)$

$=4x^2-8x-1+\left(5x^2+6x+5\right)\left(11x^4+9x^3-x^2-18\right)+9x^4-5x^3-8x^2-1$

$x^2-8x-1+55x^6+111x^5+104x^4+39x^3-95x^2-108x-90+9x^4-5x^3-8x^2-1$

$=55x^6+111x^5+113x^4+34x^3-99x^2-116x-92$

resta de polinomio

(6x²-15x-1)-(4x²+7x+3)

$\left(6x^2-15x-1\right)-\left(4x^2+7x+3\right)$

$=6x^2-15x-1-\left(4x^2+7x+3\right)$

$=6x^2-15x-1-4x^2-7x-3$

$=2x^2-22x-4$

(10u²-3u-15)-(15u²+5u-15)

$\left(10u^2-3u-15\right)-\left(15u^2+5u-15\right)$

$=10u^2-3u-15-\left(15u^2+5u-15\right)$

$=10u^2-3u-15-15u^2-5u+15$

$=-5u^2-8u$

multiplicación de monomio

(x³) (21xy)

$=x^3\cdot \:21xy\\=x^{3+1}\cdot \:21y\\=x^4\cdot \:21y\\=21x^4y$

(xy) (-5x⁴y)

$=-xy\cdot \:5x^4y\\=-x^{1+4}y\cdot \:5y\\=-x^5y\cdot \:5y\\=-x^5\cdot \:5y^{1+1}\\=-x^5\cdot \:5y^2$

(4x2) (5x²+6x-7)

$\left(4x\cdot \:2\right)\left(5x^2+6x-7\right)\\=4x\cdot \:2\left(5x^2+6x-7\right)\\=8x\left(5x^2+6x-7\right)\\=8\cdot \:5x^2x+8\cdot \:6xx-8\cdot \:7x\\=40x^3+48x^2-56x\\=8\cdot \:5x^2x+8\cdot \:6xx-8\cdot \:7x\\=8x\left(5x^2+6x-7\right)$

Explicación paso a paso:

espero te ayude me canse