Question

Solve the second-degree equiations below without expanding the product. In other words, set each factor equal to 0 and solve them separately

a) (x - 4)·(5x + 6)=0
b) (3 + 4x)·(3x + 2)=0
c)-x^2 + x + 6=0
d) 3x^2 + 5x + 2=0

Answer 1

Respuesta:

a)$(x - 4) - (5x + 6) = 0 = - \frac{5}{2}$

b)

$(3 + 4x) - (3x + 2) = 0 = -1$

c)

$- {x}^{2} + x + 6 = 0 = 0$

d)

$3x ^{2} + 5x + 2 = 0 = -\frac{2}{3} \\ x = - 1$