Question

solucionarme esto por favor con el procedimiento antes de las 18:30 APROX

A)6×(7+1/4+3×2/3)

B)(9/5 + 7 + 2/4 ) : ( 3 + 6/5 )

C)(9/5 + 7 + 2/4 ) x ( 3 + 6/5 )

D)(9/5 + 7 + 2/4 ) + ( 3 + 6/5 )

Answer 1

Respuesta:

a)$6*(7+\frac{1}{4}+\frac{6}{3})=6*(\frac{12*7+1*3+6*4}{12})=6*(\frac{84+3+24}{12})\\\\=6*\frac{111}{12}=\frac{111}{2}$

b)$\frac{(\frac{9}{5}+7+\frac{2}{4})}{3+\frac{6}{5} }=\frac{(\frac{9}{5}+7+\frac{1}{2})}{3+\frac{6}{5} }=\frac{\frac{9*2+7*10+1*5}{10}}{\frac{15+6}{5} }\\=\frac{\frac{93}{10} }{\frac{21}{5} }=\frac{93*5}{10*21}=\frac{465}{210}=\frac{31}{14}$

c)$(\frac{9}{5}+7+\frac{2}{4})*(3+\frac{6}{5})=(\frac{9}{5}+7+\frac{1}{2})*(3+\frac{6}{5} )=(\frac{9*2+7*10+1*5}{10})*({\frac{15+6}{5})\\\\={\frac{93}{10}*{\frac{21}{5}=\frac{1953}{50}$

d)$(\frac{9}{5}+7+\frac{2}{4})+(3+\frac{6}{5})=(\frac{9}{5}+7+\frac{1}{2})+(3+\frac{6}{5})\\ \\=(\frac{9*2+7*10+1*5}{10})+({\frac{15+6}{5})={\frac{93}{10}+{\frac{21}{5}\\\\=\frac{90*1+21*2}{10}=\frac{132}{10}=\frac{66}{5}$

Explicación paso a paso: