Question

solución ecuaciones de primer grado con número racionales
porfavor ayudenme es urgente ​

Answer 1

Respuesta:

$\frac{3}{4}x + \frac{5}{2} = \frac{5}{2}x - \frac{11}{4}$

$\frac{3}{4}x - \frac{5}{2}x = - \frac{11}{4} - \frac{5}{2}$

$\frac{3x - 10x}{4} = \frac{ - 11 - 10}{4}$

$- \frac{7}{4}x = - \frac{21}{4}$

$\frac{7}{4}x = \frac{21}{4}$

$x = \frac{21}{4} \times \frac{4}{7}$

x = 3

$\frac{3}{2}x + \frac{1}{6} + 2x = \frac{7}{2} - \frac{5}{6}x + 1$

$\frac{3}{2}x + 2x + \frac{5}{6}x = \frac{7}{2} + 1 - \frac{1}{6}$

$\frac{9x + 12x + 5x}{6} = \frac{21 + 6 - 1}{6}$

$\frac{26}{6}x = \frac{26}{6}$

$x = \frac{26}{6} \times \frac{6}{26}$

x = 1

$\frac{3}{4} - \frac{5}{8}x = 2$

$\frac{3}{4} - 2 = \frac{5}{8}x$

$\frac{3 - 8}{4} = \frac{5}{8}x$

$- \frac{5}{4} = \frac{5}{8}x$

$x = ( - \frac{5}{4})( \frac{8}{5})$

x = - 2

$\frac{3}{4}x - \frac{1}{5} + 2x = \frac{5}{4} - \frac{3}{20}x$

$\frac{3}{4}x + 2x + \frac{3}{20}x = \frac{5}{4} + \frac{1}{5}$

$\frac{15x + 40x + 3x}{20} = \frac{25 + 4}{20}$

$\frac{58}{20}x = \frac{29}{20}$

$x = (\frac{29}{20})( \frac{20}{58})$

$x = \frac{29}{58}$

$x = \frac{1}{2}$