Question

solucion de 81+(-(2x+4)-(3x+5))=20-(-3x+(-3x+6)

Answer 1

Respuesta:

Explicación paso a paso:

81+(-(2x+4)-(3x+5))=20-(-3x+(-3x+6))

81+(-2x-4-3x-5)=20+3x-(-3x+6)

81-5x-9= 20+3x+3x-6

81-5x-9=14+6x

58=11x

x=58/11

Answer 2

Explicación paso a paso:

$81 + ( - 2x - 4 - 3x - 5) = 20 - ( - 3x - 3x + 6) \\ 81 + ( - 5x - 9) = 20 - ( - 6x + 6) \\ 81 - 5x - 9 = 20 + 6x - 6 \\ 72 - 5x = 14 + 6x \\ - 5x - 6x = 14 - 72 \\ - 11x = - 58 \\ x = \frac{58}{11} \\ \\ comprobación \: \\ 81 + ( - 2 \times \frac{58}{11} - 4 - 3 \times \frac{58}{11} - 5) = 20 - ( - 3 \times \frac{58}{11} - 3 \times \frac{58}{11} + 6) \\ \\ 81 + ( - \frac{116}{11} - 4 - \frac{174}{11} - 5) = 20 - ( - \frac{174}{11} - \frac{174}{11} + 6) \\ \\ 81 + ( \frac{ - 116 - 44 - 174 - 55}{11} ) = 20 - ( \frac{ - 174 - 174 + 66}{11} ) \\ \\ 81 + ( - \frac{389}{11} ) = 20 - ( - \frac{282}{11} ) \\ \\ 81 - \frac{389}{11} = 20 + \frac{282}{11} \\ \\ \frac{891 - 389}{11} = \frac{220 + 282}{11} \\ \\ \frac{502}{11} = \frac{502}{11}$