Question

sistemas de ecuaciones
2x+3y=2
6x-6y=1

Answer 1

$2x+3y=2 ........(1)\\ 6x-6y=1.........(2) \\ en \: ecuacion(2) \: despejamos \\ (3y) \\ 6x-6y=1 \\ factorizando \\ - 2( - 3x + 3y )= 1 \\ - 3x + 3y = - \frac{1}{2} \\ 3y = 3x - \frac{1}{2} .........(3)en(1) \\ 2x+3y=2 \\ 2x+3x - \frac{1}{2}=2 \\ 5x = 2 + \frac{1}{2} \\ 5x = \frac{4 + 1}{2} \\ 5x = \frac{5}{2} \\ x = \frac{5}{2 \times 5} simplificamos \: (5) \\ x = \: \frac{1}{2} respuesta \: en(3) \\ 3y = 3x - \frac{1}{2} \\ 3y = 3 \times \frac{1}{2} - \frac{1}{2} \\ 3y = \frac{3 - 1}{2} \\ 3y = \frac{2}{2} \\ 3y = 1 \\ y = \frac{1}{3} respuesta$