Sistema de ecuaciones con dos incognitas
metodo de reducción.
4(2-x)= 3y
2(2-x) = 2(y-2)
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Answer:
We have
4x + 3y = 8 (i)
2x + 2y = 8 (ii)
So multiplying the equation (ii) by 2 we have 4x + 4y =16 (iii)
Hence, subtracting (i) from (iii) we have
y = 8. Therefore, substituting y in either of the first two equations you have
x = -4
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