Question

Simplificar:
$1. \frac{secx +tgx }{1 + senx}$
$2.4senx + 2tgx \times cscx$
$3. \frac{1}{senx} + \frac{1}{cosx} - secx + cscx$
$4.cosx(1 - secx) + 1$
​

Answer 1

Explicación paso a paso:

$\frac{( \frac{1}{ \cos(x) } + \frac{ \sin(x) }{ \cos(x) } )}{1 + \sin(x) } = \frac{ \frac{1 + \sin(x) }{ \cos(x) } }{1 + \sin(x) } = \frac{1}{ \cos(x) }$

$4 \sin(x) + 2 \frac{ \sin(x) }{ \cos(x) } \times \frac{1}{ \sin(x) } = 4 \sin(x) + \frac{2}{ \cos(x) }$

$\frac{1}{ \sin(x) } + \frac{1}{ \cos(x) } - \frac{1}{ \cos(x) } + \frac{1}{ \sin(x) } = \frac{2}{ \sin(x) }$

$\cos(x) (1 - \frac{1}{ \cos(x) } ) + 1 = \cos(x) - 1 + 1 = \cos(x)$