Question

simplificar [1/x - 1/x-1 + 2/x^2-1] × (x/x+1)​

Answer 1

Respuesta:

B)

Explicación paso a paso:

$\left(\frac{1}{x}-\frac{1}{x-1}+\frac{2}{x^2-1}\right)\left(\frac{x}{x+1}\right)^{-1}$

$=\frac{1}{\left(\frac{x}{x+1}\right)}\left(\frac{1}{x}+\frac{2}{x^2-1}-\frac{1}{x-1}\right)$

$=\frac{1}{x\left(x+1\right)}\times \frac{1}{\frac{x}{x+1}}$

$=\frac{1\times \left(x+1\right)}{x\left(x+1\right)x}$

$=\frac{1}{xx}$

$=\frac{1}{x^2}$

$=x^{-2}$