simplificar 1.(-32)¹/⁵ 2.(-27)²/³ 3.(0,008)¹/³
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![(-32)^{ \frac{1}{5} } = \sqrt[5]{-32^{1}} = -2 \\ \\ (-27)^{ \frac{2}{3}} = \sqrt[3]{(-27) ^{2}} = 9 \\ \\ 0.008^{ \frac{1}{3}} = \left(\dfrac{8:8}{1000:8}\right)= \left( \dfrac{1}{125}\right)^{ \dfrac{1}{3}} = \sqrt[3]{125} = 5](https://tex.z-dn.net/?f=+%28-32%29%5E%7B+%5Cfrac%7B1%7D%7B5%7D+%7D+%3D++%5Csqrt%5B5%5D%7B-32%5E%7B1%7D%7D+%3D++-2+%5C%5C+%5C%5C++%28-27%29%5E%7B+%5Cfrac%7B2%7D%7B3%7D%7D+%3D+%5Csqrt%5B3%5D%7B%28-27%29+%5E%7B2%7D%7D+%3D+9+%5C%5C+%5C%5C+0.008%5E%7B+%5Cfrac%7B1%7D%7B3%7D%7D+%3D++%5Cleft%28%5Cdfrac%7B8%3A8%7D%7B1000%3A8%7D%5Cright%29%3D+%5Cleft%28+%5Cdfrac%7B1%7D%7B125%7D%5Cright%29%5E%7B+%5Cdfrac%7B1%7D%7B3%7D%7D+%3D++%5Csqrt%5B3%5D%7B125%7D+%3D++5+ "(-32)^{ \frac{1}{5} } = \sqrt[5]{-32^{1}} = -2 \\ \\ (-27)^{ \frac{2}{3}} = \sqrt[3]{(-27) ^{2}} = 9 \\ \\ 0.008^{ \frac{1}{3}} = \left(\dfrac{8:8}{1000:8}\right)= \left( \dfrac{1}{125}\right)^{ \dfrac{1}{3}} = \sqrt[3]{125} = 5")
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