Question

Signos de agrupaciones de -2[4(-y-3)-(2y+1)]=10y-6​

Answer 1

2[4(-y-3) - (2y+1)] = 10y-6​

2[ -4y - 12 - 2y - 1] = 10y - 6

​2[ -6y - 13 ] = 10y - 6

​-12y - 26  = 10y - 6

- 26 + 6 = 10y + 12y

-20 =  22y

-20/22 = y

-10/11 = y

Eternamente axllxa

Answer 2

Respuesta:

2[4(-y-3) - (2y+1)] = 10y-6​

2[ -4y - 12 - 2y - 1] = 10y - 6

​2[ -6y - 13 ] = 10y - 6

​-12y - 26  = 10y - 6

- 26 + 6 = 10y + 12y

-20 =  22y

-20/22 = y

-10/11 = y

Explicación paso a paso: