Question

SiB(x)=x^{4}-5x^{2}+7x-20 Y sabiendo quex=0 Resuelve: B(0)=

Answer 1

$b(x) = {x}^{4} - 5 {x}^{2} + 7x - 20$

$b(0) = {0}^{4} - 5 \times {0}^{2} + 7 \times 0 - 20$

$b(0) = 0 - 5 \times 0 + 0 - 20$

$b(0) = 0 - 0 + 0 - 20$

$b(0) = - 20$