Question

Si, x² + y²=13
x-y=5
calcula P=xy
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Answer 1

Respuesta:

6

Explicación paso a paso:

Si, x² + y² = 13

x - y = 5

Calcula P = x . y

x = 5 + y

25 + 2.5y + y² + y² = 13

25 + 10y + 2y² = 13

2y² + 10y + 12 = 0

y₁,₂ = ( -10 ± √(10² - 4 . 2 . 12 ) ) / 2 . 2

y₁,₂ = ( -10 ± √(100 - 96 ) ) / 4

y₁,₂ = ( -10 ± √4 ) / 4

y₁,₂ = ( -10 ± 2 ) / 4

y₁ = ( -10 + 2 ) / 4

y₁ = -8 / 4 = -2

y₂ = ( -10 - 2 ) / 4

y₂ = -12 / 4 = -3

Con y₁

x² + (-2)² = 13

x² + 4 = 13

x² = 9

x = 3

x - (-2) = 5

3 + 2 = 5

x . y = 3 * 2 = 6

Con y₂

x² + (-3)² = 13

x² + 9 = 13

x² = 4

x = 2

x - (-3) = 5

2 + 3 = 5

x . y = 2 * 3 = 6

Espero que te halla servido :)