Question

si x-n=8 reducir: 64x2n+x-2n

Answer 1

si x-n = 8 entonces:
64x2n+x-2n
128xn+x-n-n
128xn+8-n
8(16xn+1)-n
8(16x(x-8)+1)-(x-8) pesto que n=x-8
8(16x^2 - 128 + 1) - (x-8)
128x^2 - 1016 - x + 8
128x^2 - x - 1008
16(8x^2 - 63) - x

Answer 2

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