Question

Si, x/3=y/2=z; x. y. z =6^4, halla: x+y+z​

Answer 1

☆ RESOLUCIÓN:

$\frac{x}{3} = \frac{y}{2} = z$

$→ \boxed{x = 3z}$

$→ \boxed{y = 2z}$

$⇒x \times y \times z = {6}^{4} \\ 3z \times 2z \times z = 1296 \\ 6 {z}^{3} = 1296 \\ {z}^{3} = \frac{1296}{6} \\ {z}^{3} = 216 \\ z = \sqrt[3]{216} \\  \boxed{z = 6}$

$⇒x + y + z \\ 3z + 2z + z \\ 6z \\ 6 \times 6 \\  \boxed{36}$

☆ RESPUESTA:

$\boxed{x + y + z = 36}$