Question

Si.x^2+3x=5, calcule el valor de
(x+5)(x+2)(x+1)(x-2)​

Answer 1

Respuesta:

-35

Explicación paso a paso:

(x+5)(x+1)(x+2)(x-2)

$(x^{2} +6x+5)(x^{2} -4)\\(x^{2} +3x+3x+5)(x^{2} -4)\\(5+3x+5)(5-3x-4)\\(3x+10)(1-3x)\\-9x^{2} -27x+10\\-9(x^{2} +3x)+10\\-9(5)+10\\-35$

Answer 2

-35 (x+5)(x+1)(x+2)(x-2)

(x

2

+6x+5)(x

2

−4)

(x

2

+3x+3x+5)(x

2

−4)

(5+3x+5)(5−3x−4)

(3x+10)(1−3x)

−9x

2

−27x+10

−9(x

2

+3x)+10

−9(5)+10

−35